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(2x+5)(8x+3)=0
We multiply parentheses ..
(+16x^2+6x+40x+15)=0
We get rid of parentheses
16x^2+6x+40x+15=0
We add all the numbers together, and all the variables
16x^2+46x+15=0
a = 16; b = 46; c = +15;
Δ = b2-4ac
Δ = 462-4·16·15
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-34}{2*16}=\frac{-80}{32} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+34}{2*16}=\frac{-12}{32} =-3/8 $
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