(2x+5)(x-1=-6

Solution for (2x+5)(x-1=-6 equation:

(2x+5)(x-1=-6

We move all terms to the left:

(2x+5)(x-1-(-6)=0


We calculate terms in parentheses: +(2x+5)(x-1-(-6), so:

2x+5)(x-1-(-6

We add all the numbers together, and all the variables

2x+5)(x

Back to the equation:

+(2x+5)(x)


We multiply parentheses

2x^2+5x=0

a = 2; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·2·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*2}=\frac{-10}{4}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*2}=\frac{0}{4}
=0
$