(2x+5)(x-3)(3x+1)=39

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Solution for (2x+5)(x-3)(3x+1)=39 equation: 



(2x+5)(x-3)(3x+1)=39

We move all terms to the left:

(2x+5)(x-3)(3x+1)-(39)=0

We multiply parentheses ..

(+2x^2-6x+5x-15)(3x+1)-39=0

We move all terms containing x to the left, all other terms to the right

(+2x^2-6x+5x-15)(3x+1)=39

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