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(2x+5)(x-3)(3x+1)=39
We move all terms to the left:
(2x+5)(x-3)(3x+1)-(39)=0
We multiply parentheses ..
(+2x^2-6x+5x-15)(3x+1)-39=0
We move all terms containing x to the left, all other terms to the right
(+2x^2-6x+5x-15)(3x+1)=39
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