(2x+5)+(31)=(4x-10)

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Solution for (2x+5)+(31)=(4x-10) equation: 



(2x+5)+(31)=(4x-10)

We move all terms to the left:

(2x+5)+(31)-((4x-10))=0

We get rid of parentheses

2x-((4x-10))+5+31=0



We calculate terms in parentheses: -((4x-10)), so:

(4x-10)

We get rid of parentheses

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

2x-(4x-10)+36=0

We get rid of parentheses

2x-4x+10+36=0

We add all the numbers together, and all the variables

-2x+46=0

We move all terms containing x to the left, all other terms to the right

-2x=-46

x=-46/-2

x=+23

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