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(2x+5)+(3x-4)=9/2
We move all terms to the left:
(2x+5)+(3x-4)-(9/2)=0
We add all the numbers together, and all the variables
(2x+5)+(3x-4)-(+9/2)=0
We get rid of parentheses
2x+3x+5-4-9/2=0
We multiply all the terms by the denominator
2x*2+3x*2-9+5*2-4*2=0
We add all the numbers together, and all the variables
2x*2+3x*2-7=0
Wy multiply elements
4x+6x-7=0
We add all the numbers together, and all the variables
10x-7=0
We move all terms containing x to the left, all other terms to the right
10x=7
x=7/10
x=7/10
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