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(2x+5)+(4x+6)=(2x+4x)+(5+6)
We move all terms to the left:
(2x+5)+(4x+6)-((2x+4x)+(5+6))=0
We add all the numbers together, and all the variables
(2x+5)+(4x+6)-((+6x)+11)=0
We get rid of parentheses
2x+4x-((+6x)+11)+5+6=0
We calculate terms in parentheses: -((+6x)+11), so:We add all the numbers together, and all the variables
(+6x)+11
We get rid of parentheses
6x+11
Back to the equation:
-(6x+11)
6x-(6x+11)+11=0
We get rid of parentheses
6x-6x-11+11=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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