(2x+5)+(7x+3)+10=340

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Solution for (2x+5)+(7x+3)+10=340 equation: 



(2x+5)+(7x+3)+10=340

We move all terms to the left:

(2x+5)+(7x+3)+10-(340)=0

We add all the numbers together, and all the variables

(2x+5)+(7x+3)-330=0

We get rid of parentheses

2x+7x+5+3-330=0

We add all the numbers together, and all the variables

9x-322=0

We move all terms containing x to the left, all other terms to the right

9x=322

x=322/9

x=35+7/9

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