If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x+5)-(5x+2)x=8
We move all terms to the left:
(2x+5)-(5x+2)x-(8)=0
We multiply parentheses
-5x^2+(2x+5)-2x-8=0
We get rid of parentheses
-5x^2+2x-2x+5-8=0
We add all the numbers together, and all the variables
-5x^2-3=0
a = -5; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-5)·(-3)
Δ = -60
Delta is less than zero, so there is no solution for the equation
| 5c+c=6c | | 10y-5=-6y+27 | | 35=c+17 | | (5)=1.5x+1 | | 5/n=28.5/0.25 | | 25=4x+2.20 | | y/4+y/6=y-7 | | 46-x=91 | | 4y+2y=21 | | H(t)=-16(t-21/16)^2+1993/16 | | 12=14-2d | | -15y-30=2y-5 | | 13-2y=-11 | | -2(n+1)=-1(2n+5 | | 2x1=91- | | 15a=62-10 | | (5x+1)3=15x+3* | | P-15=28,p= | | 8h+12=8h | | 7+6=b/8 | | 6x²+12x-15=0 | | 91=2x-1+x | | 3/5a=62-10 | | 25(x+10=3x+15 | | 2x-1=91 | | 2(x+12)=12x= | | 8/6x=-48 | | 11–6x=0.8x^2 | | 2x-1=91-x | | 6v^2+7v-5=0 | | -1/3=4/9s= | | H(t)=-16t^2+42t+97 |