(2x+5)/2-(3x)/(x-2)=x

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Solution for (2x+5)/2-(3x)/(x-2)=x equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(2*x+5)/2-((3*x)/(x-2)) = x // - x

(2*x+5)/2-((3*x)/(x-2))-x = 0

(2*x+5)/2-3*x*(x-2)^-1-x = 0

(2*x+5)/2+(-3*x)/(x-2)-x = 0

((2*x+5)*(x-2))/(2*(x-2))+(-3*2*x)/(2*(x-2))+(2*(-x)*(x-2))/(2*(x-2)) = 0

(2*x+5)*(x-2)+2*(-x)*(x-2)-3*2*x = 0

2*x^2-2*x^2-5*x+4*x-10 = 0

-x-10 = 0

(-x-10)/(2*(x-2)) = 0

(-x-10)/(2*(x-2)) = 0 // * 2*(x-2)

-x-10 = 0

-x-10 = 0 // + 10

-x = 10 // * -1

x = -10

x = -10

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