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(2x+5)/3x=5/8
We move all terms to the left:
(2x+5)/3x-(5/8)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
(2x+5)/3x-(+5/8)=0
We get rid of parentheses
(2x+5)/3x-5/8=0
We calculate fractions
(16x+40)/24x+(-15x)/24x=0
We multiply all the terms by the denominator
(16x+40)+(-15x)=0
We get rid of parentheses
16x-15x+40=0
We add all the numbers together, and all the variables
x+40=0
We move all terms containing x to the left, all other terms to the right
x=-40
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