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(2x+5)/x=2x/(x-3)
We move all terms to the left:
(2x+5)/x-(2x/(x-3))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x-3))!=0We calculate fractions
x∈R
-2x^2)+(-(2x*x)/(-2x^2)+((2x+5)*(x-3)))/(=0
We add all the numbers together, and all the variables
-2x^2)+(-(+2x*x)/(-2x^2)+((2x+5)*(x-3)))/(=0
We calculate fractions
-2x^2)+(+(-(+2x*x)*()/((-2x^2)*()+(-2x^2)+((2x+5)*(x-3)))*()/((-2x^2)*()=0
We calculate terms in parentheses: +(-(+2x*x)*()/((-2x^2)*()+(-2x^2)+((2x+5)*(x-3)))*()/((-2x^2)*(), so:
-(+2x*x)*()/((-2x^2)*()+(-2x^2)+((2x+5)*(x-3)))*()/((-2x^2)*(
We can not solve this equation
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