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(2x+5)3x=360
We move all terms to the left:
(2x+5)3x-(360)=0
We multiply parentheses
6x^2+15x-360=0
a = 6; b = 15; c = -360;
Δ = b2-4ac
Δ = 152-4·6·(-360)
Δ = 8865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8865}=\sqrt{9*985}=\sqrt{9}*\sqrt{985}=3\sqrt{985}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3\sqrt{985}}{2*6}=\frac{-15-3\sqrt{985}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3\sqrt{985}}{2*6}=\frac{-15+3\sqrt{985}}{12} $
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