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(2x+5)=(25)(8x)
We move all terms to the left:
(2x+5)-((25)(8x))=0
determiningTheFunctionDomain (2x+5)-258x=0
We add all the numbers together, and all the variables
-258x+(2x+5)=0
We get rid of parentheses
-258x+2x+5=0
We add all the numbers together, and all the variables
-256x+5=0
We move all terms containing x to the left, all other terms to the right
-256x=-5
x=-5/-256
x=5/256
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