(2x+5)=(3x-23)

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Solution for (2x+5)=(3x-23) equation: 



(2x+5)=(3x-23)

We move all terms to the left:

(2x+5)-((3x-23))=0

We get rid of parentheses

2x-((3x-23))+5=0



We calculate terms in parentheses: -((3x-23)), so:

(3x-23)

We get rid of parentheses

3x-23

Back to the equation:

-(3x-23)



We get rid of parentheses

2x-3x+23+5=0

We add all the numbers together, and all the variables

-1x+28=0

We move all terms containing x to the left, all other terms to the right

-x=-28

x=-28/-1

x=+28

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