(2x+5)=(3x-27)=69

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Solution for (2x+5)=(3x-27)=69 equation: 



(2x+5)=(3x-27)=69

We move all terms to the left:

(2x+5)-((3x-27))=0

We get rid of parentheses

2x-((3x-27))+5=0



We calculate terms in parentheses: -((3x-27)), so:

(3x-27)

We get rid of parentheses

3x-27

Back to the equation:

-(3x-27)



We get rid of parentheses

2x-3x+27+5=0

We add all the numbers together, and all the variables

-1x+32=0

We move all terms containing x to the left, all other terms to the right

-x=-32

x=-32/-1

x=+32

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