(2x+5)=(3x-70)

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Solution for (2x+5)=(3x-70) equation:



(2x+5)=(3x-70)
We move all terms to the left:
(2x+5)-((3x-70))=0
We get rid of parentheses
2x-((3x-70))+5=0
We calculate terms in parentheses: -((3x-70)), so:
(3x-70)
We get rid of parentheses
3x-70
Back to the equation:
-(3x-70)
We get rid of parentheses
2x-3x+70+5=0
We add all the numbers together, and all the variables
-1x+75=0
We move all terms containing x to the left, all other terms to the right
-x=-75
x=-75/-1
x=+75

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