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(2x+5)=(5x+11)+(2x+11)
We move all terms to the left:
(2x+5)-((5x+11)+(2x+11))=0
We get rid of parentheses
2x-((5x+11)+(2x+11))+5=0
We calculate terms in parentheses: -((5x+11)+(2x+11)), so:We get rid of parentheses
(5x+11)+(2x+11)
We get rid of parentheses
5x+2x+11+11
We add all the numbers together, and all the variables
7x+22
Back to the equation:
-(7x+22)
2x-7x-22+5=0
We add all the numbers together, and all the variables
-5x-17=0
We move all terms containing x to the left, all other terms to the right
-5x=17
x=17/-5
x=-3+2/5
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