(2x+5)=(5x+28)

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Solution for (2x+5)=(5x+28) equation: 



(2x+5)=(5x+28)

We move all terms to the left:

(2x+5)-((5x+28))=0

We get rid of parentheses

2x-((5x+28))+5=0



We calculate terms in parentheses: -((5x+28)), so:

(5x+28)

We get rid of parentheses

5x+28

Back to the equation:

-(5x+28)



We get rid of parentheses

2x-5x-28+5=0

We add all the numbers together, and all the variables

-3x-23=0

We move all terms containing x to the left, all other terms to the right

-3x=23

x=23/-3

x=-7+2/3

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