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(2x+5)=3(3x-10)
We move all terms to the left:
(2x+5)-(3(3x-10))=0
We get rid of parentheses
2x-(3(3x-10))+5=0
We calculate terms in parentheses: -(3(3x-10)), so:We get rid of parentheses
3(3x-10)
We multiply parentheses
9x-30
Back to the equation:
-(9x-30)
2x-9x+30+5=0
We add all the numbers together, and all the variables
-7x+35=0
We move all terms containing x to the left, all other terms to the right
-7x=-35
x=-35/-7
x=+5
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