(2x+5-7/3)=36

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Solution for (2x+5-7/3)=36 equation: 



(2x+5-7/3)=36

We move all terms to the left:

(2x+5-7/3)-(36)=0

We add all the numbers together, and all the variables

(2x-7/3+5)-36=0

We get rid of parentheses

2x+5-36-7/3=0

We multiply all the terms by the denominator


2x*3-7+5*3-36*3=0

We add all the numbers together, and all the variables

2x*3-100=0

Wy multiply elements

6x-100=0

We move all terms containing x to the left, all other terms to the right

6x=100

x=100/6

x=16+2/3

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