(2x+5.2)+(3x+1.2)+(2x+6.2)=180

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Solution for (2x+5.2)+(3x+1.2)+(2x+6.2)=180 equation: 



(2x+5.2)+(3x+1.2)+(2x+6.2)=180

We move all terms to the left:

(2x+5.2)+(3x+1.2)+(2x+6.2)-(180)=0

We get rid of parentheses

2x+3x+2x+5.2+1.2+6.2-180=0

We add all the numbers together, and all the variables

7x-167.4=0

We move all terms containing x to the left, all other terms to the right

7x=167.4

x=167.4/7

x=23+4.5714285714286/5

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