(2x+50)(3x)=90

Solution for (2x+50)(3x)=90 equation:

(2x+50)(3x)=90

We move all terms to the left:

(2x+50)(3x)-(90)=0

We multiply parentheses

6x^2+150x-90=0

a = 6; b = 150; c = -90;
Δ = b2-4ac
Δ = 1502-4·6·(-90)
Δ = 24660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24660}=\sqrt{36*685}=\sqrt{36}*\sqrt{685}=6\sqrt{685}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-6\sqrt{685}}{2*6}=\frac{-150-6\sqrt{685}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+6\sqrt{685}}{2*6}=\frac{-150+6\sqrt{685}}{12}
$