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(2x+50)+(5x+15)=100
We move all terms to the left:
(2x+50)+(5x+15)-(100)=0
We get rid of parentheses
2x+5x+50+15-100=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
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