(2x+50)+4x+(3x-5)=180

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Solution for (2x+50)+4x+(3x-5)=180 equation: 



(2x+50)+4x+(3x-5)=180

We move all terms to the left:

(2x+50)+4x+(3x-5)-(180)=0

We add all the numbers together, and all the variables

4x+(2x+50)+(3x-5)-180=0

We get rid of parentheses

4x+2x+3x+50-5-180=0

We add all the numbers together, and all the variables

9x-135=0

We move all terms containing x to the left, all other terms to the right

9x=135

x=135/9

x=15

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