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(2x+51)(5x+4)=90
We move all terms to the left:
(2x+51)(5x+4)-(90)=0
We multiply parentheses ..
(+10x^2+8x+255x+204)-90=0
We get rid of parentheses
10x^2+8x+255x+204-90=0
We add all the numbers together, and all the variables
10x^2+263x+114=0
a = 10; b = 263; c = +114;
Δ = b2-4ac
Δ = 2632-4·10·114
Δ = 64609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(263)-\sqrt{64609}}{2*10}=\frac{-263-\sqrt{64609}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(263)+\sqrt{64609}}{2*10}=\frac{-263+\sqrt{64609}}{20} $
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