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(2x+53)=(x+60)
We move all terms to the left:
(2x+53)-((x+60))=0
We get rid of parentheses
2x-((x+60))+53=0
We calculate terms in parentheses: -((x+60)), so:We get rid of parentheses
(x+60)
We get rid of parentheses
x+60
Back to the equation:
-(x+60)
2x-x-60+53=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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