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(2x+55)(x-15)=180
We move all terms to the left:
(2x+55)(x-15)-(180)=0
We multiply parentheses ..
(+2x^2-30x+55x-825)-180=0
We get rid of parentheses
2x^2-30x+55x-825-180=0
We add all the numbers together, and all the variables
2x^2+25x-1005=0
a = 2; b = 25; c = -1005;
Δ = b2-4ac
Δ = 252-4·2·(-1005)
Δ = 8665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{8665}}{2*2}=\frac{-25-\sqrt{8665}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{8665}}{2*2}=\frac{-25+\sqrt{8665}}{4} $
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