(2x+58)=(6x+10)

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Solution for (2x+58)=(6x+10) equation: 



(2x+58)=(6x+10)

We move all terms to the left:

(2x+58)-((6x+10))=0

We get rid of parentheses

2x-((6x+10))+58=0



We calculate terms in parentheses: -((6x+10)), so:

(6x+10)

We get rid of parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

2x-6x-10+58=0

We add all the numbers together, and all the variables

-4x+48=0

We move all terms containing x to the left, all other terms to the right

-4x=-48

x=-48/-4

x=+12

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