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(2x+59)+(x-19)+x=180
We move all terms to the left:
(2x+59)+(x-19)+x-(180)=0
We add all the numbers together, and all the variables
x+(2x+59)+(x-19)-180=0
We get rid of parentheses
x+2x+x+59-19-180=0
We add all the numbers together, and all the variables
4x-140=0
We move all terms containing x to the left, all other terms to the right
4x=140
x=140/4
x=35
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