(2x+5y)(2x-5y)=0

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Solution for (2x+5y)(2x-5y)=0 equation:


Simplifying
(2x + 5y)(2x + -5y) = 0

Multiply (2x + 5y) * (2x + -5y)
(2x * (2x + -5y) + 5y * (2x + -5y)) = 0
((2x * 2x + -5y * 2x) + 5y * (2x + -5y)) = 0

Reorder the terms:
((-10xy + 4x2) + 5y * (2x + -5y)) = 0
((-10xy + 4x2) + 5y * (2x + -5y)) = 0
(-10xy + 4x2 + (2x * 5y + -5y * 5y)) = 0
(-10xy + 4x2 + (10xy + -25y2)) = 0

Reorder the terms:
(-10xy + 10xy + 4x2 + -25y2) = 0

Combine like terms: -10xy + 10xy = 0
(0 + 4x2 + -25y2) = 0
(4x2 + -25y2) = 0

Solving
4x2 + -25y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '25y2' to each side of the equation.
4x2 + -25y2 + 25y2 = 0 + 25y2

Combine like terms: -25y2 + 25y2 = 0
4x2 + 0 = 0 + 25y2
4x2 = 0 + 25y2
Remove the zero:
4x2 = 25y2

Divide each side by '4'.
x2 = 6.25y2

Simplifying
x2 = 6.25y2

Take the square root of each side:
x = {-2.5y, 2.5y}

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