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(2x+6)(2x+4)-24=56
We move all terms to the left:
(2x+6)(2x+4)-24-(56)=0
We add all the numbers together, and all the variables
(2x+6)(2x+4)-80=0
We multiply parentheses ..
(+4x^2+8x+12x+24)-80=0
We get rid of parentheses
4x^2+8x+12x+24-80=0
We add all the numbers together, and all the variables
4x^2+20x-56=0
a = 4; b = 20; c = -56;
Δ = b2-4ac
Δ = 202-4·4·(-56)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-36}{2*4}=\frac{-56}{8} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+36}{2*4}=\frac{16}{8} =2 $
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