(2x+6)(3x+12)=0

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Solution for (2x+6)(3x+12)=0 equation:



(2x+6)(3x+12)=0
We multiply parentheses ..
(+6x^2+24x+18x+72)=0
We get rid of parentheses
6x^2+24x+18x+72=0
We add all the numbers together, and all the variables
6x^2+42x+72=0
a = 6; b = 42; c = +72;
Δ = b2-4ac
Δ = 422-4·6·72
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6}{2*6}=\frac{-48}{12} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6}{2*6}=\frac{-36}{12} =-3 $

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