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(2x+6)(3x-1)=0
We multiply parentheses ..
(+6x^2-2x+18x-6)=0
We get rid of parentheses
6x^2-2x+18x-6=0
We add all the numbers together, and all the variables
6x^2+16x-6=0
a = 6; b = 16; c = -6;
Δ = b2-4ac
Δ = 162-4·6·(-6)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20}{2*6}=\frac{-36}{12} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20}{2*6}=\frac{4}{12} =1/3 $
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