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(2x+6)(3x-11)=0
We multiply parentheses ..
(+6x^2-22x+18x-66)=0
We get rid of parentheses
6x^2-22x+18x-66=0
We add all the numbers together, and all the variables
6x^2-4x-66=0
a = 6; b = -4; c = -66;
Δ = b2-4ac
Δ = -42-4·6·(-66)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-40}{2*6}=\frac{-36}{12} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+40}{2*6}=\frac{44}{12} =3+2/3 $
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