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(2x+6)(5x-3)=0
We multiply parentheses ..
(+10x^2-6x+30x-18)=0
We get rid of parentheses
10x^2-6x+30x-18=0
We add all the numbers together, and all the variables
10x^2+24x-18=0
a = 10; b = 24; c = -18;
Δ = b2-4ac
Δ = 242-4·10·(-18)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*10}=\frac{-60}{20} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*10}=\frac{12}{20} =3/5 $
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