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(2x+6)(5x-8)=0
We multiply parentheses ..
(+10x^2-16x+30x-48)=0
We get rid of parentheses
10x^2-16x+30x-48=0
We add all the numbers together, and all the variables
10x^2+14x-48=0
a = 10; b = 14; c = -48;
Δ = b2-4ac
Δ = 142-4·10·(-48)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-46}{2*10}=\frac{-60}{20} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+46}{2*10}=\frac{32}{20} =1+3/5 $
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