(2x+6)(7-4x)=(2-x)(8x+1)+15

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Solution for (2x+6)(7-4x)=(2-x)(8x+1)+15 equation: 



(2x+6)(7-4x)=(2-x)(8x+1)+15

We move all terms to the left:

(2x+6)(7-4x)-((2-x)(8x+1)+15)=0

We add all the numbers together, and all the variables

(2x+6)(-4x+7)-((-1x+2)(8x+1)+15)=0

We multiply parentheses ..

(-8x^2+14x-24x+42)-((-1x+2)(8x+1)+15)=0



We calculate terms in parentheses: -((-1x+2)(8x+1)+15), so:

(-1x+2)(8x+1)+15

We multiply parentheses ..

(-8x^2-1x+16x+2)+15

We get rid of parentheses

-8x^2-1x+16x+2+15

We add all the numbers together, and all the variables

-8x^2+15x+17

Back to the equation:

-(-8x^2+15x+17)



We get rid of parentheses

-8x^2+8x^2+14x-24x-15x+42-17=0

We add all the numbers together, and all the variables

-25x+25=0

We move all terms containing x to the left, all other terms to the right

-25x=-25

x=-25/-25

x=1

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