(2x+6)(7-4x)=(2-x)(8x=1)+15

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Solution for (2x+6)(7-4x)=(2-x)(8x=1)+15 equation: 



(2x+6)(7-4x)=(2-x)(8x=1)+15

We move all terms to the left:

(2x+6)(7-4x)-((2-x)(8x)=0

We add all the numbers together, and all the variables

(2x+6)(-4x+7)-((-1x+2)8x=0

We multiply parentheses ..

(-8x^2+14x-24x+42)-((-1x+2)8x=0

We get rid of parentheses

-8x^2+14x-24x-((-1x+2)8x+42=0

We add all the numbers together, and all the variables

-8x^2-10x-((-1x+2)8x+42=0

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