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(2x+6)(x+2)=180
We move all terms to the left:
(2x+6)(x+2)-(180)=0
We multiply parentheses ..
(+2x^2+4x+6x+12)-180=0
We get rid of parentheses
2x^2+4x+6x+12-180=0
We add all the numbers together, and all the variables
2x^2+10x-168=0
a = 2; b = 10; c = -168;
Δ = b2-4ac
Δ = 102-4·2·(-168)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-38}{2*2}=\frac{-48}{4} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+38}{2*2}=\frac{28}{4} =7 $
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