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(2x+6)(2x+3)=54
We move all terms to the left:
(2x+6)(2x+3)-(54)=0
We multiply parentheses ..
(+4x^2+6x+12x+18)-54=0
We get rid of parentheses
4x^2+6x+12x+18-54=0
We add all the numbers together, and all the variables
4x^2+18x-36=0
a = 4; b = 18; c = -36;
Δ = b2-4ac
Δ = 182-4·4·(-36)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*4}=\frac{-48}{8} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*4}=\frac{12}{8} =1+1/2 $
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