(2x+6)*(4x-8)=192

Solution for (2x+6)*(4x-8)=192 equation:

(2x+6)(4x-8)=192

We move all terms to the left:

(2x+6)(4x-8)-(192)=0

We multiply parentheses ..

(+8x^2-16x+24x-48)-192=0

We get rid of parentheses

8x^2-16x+24x-48-192=0

We add all the numbers together, and all the variables

8x^2+8x-240=0

a = 8; b = 8; c = -240;
Δ = b2-4ac
Δ = 82-4·8·(-240)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-88}{2*8}=\frac{-96}{16}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+88}{2*8}=\frac{80}{16}
=5
$