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(2x+6)(4x-8)=192
We move all terms to the left:
(2x+6)(4x-8)-(192)=0
We multiply parentheses ..
(+8x^2-16x+24x-48)-192=0
We get rid of parentheses
8x^2-16x+24x-48-192=0
We add all the numbers together, and all the variables
8x^2+8x-240=0
a = 8; b = 8; c = -240;
Δ = b2-4ac
Δ = 82-4·8·(-240)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-88}{2*8}=\frac{-96}{16} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+88}{2*8}=\frac{80}{16} =5 $
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