(2x+6)+(2x+4)=(3x-2)+(3x-1)

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Solution for (2x+6)+(2x+4)=(3x-2)+(3x-1) equation: 



(2x+6)+(2x+4)=(3x-2)+(3x-1)

We move all terms to the left:

(2x+6)+(2x+4)-((3x-2)+(3x-1))=0

We get rid of parentheses

2x+2x-((3x-2)+(3x-1))+6+4=0



We calculate terms in parentheses: -((3x-2)+(3x-1)), so:

(3x-2)+(3x-1)

We get rid of parentheses

3x+3x-2-1

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

4x-(6x-3)+10=0

We get rid of parentheses

4x-6x+3+10=0

We add all the numbers together, and all the variables

-2x+13=0

We move all terms containing x to the left, all other terms to the right

-2x=-13

x=-13/-2

x=6+1/2

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