(2x+6)+(2x+5)+(2x)=(2x+22x)+(3x+5)

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Solution for (2x+6)+(2x+5)+(2x)=(2x+22x)+(3x+5) equation: 



(2x+6)+(2x+5)+(2x)=(2x+22x)+(3x+5)

We move all terms to the left:

(2x+6)+(2x+5)+(2x)-((2x+22x)+(3x+5))=0

We add all the numbers together, and all the variables

(2x+6)+(2x+5)+2x-((+24x)+(3x+5))=0

We add all the numbers together, and all the variables

2x+(2x+6)+(2x+5)-((+24x)+(3x+5))=0

We get rid of parentheses

2x+2x+2x-((+24x)+(3x+5))+6+5=0



We calculate terms in parentheses: -((+24x)+(3x+5)), so:

(+24x)+(3x+5)

We get rid of parentheses

24x+3x+5

We add all the numbers together, and all the variables

27x+5

Back to the equation:

-(27x+5)



We add all the numbers together, and all the variables

6x-(27x+5)+11=0

We get rid of parentheses

6x-27x-5+11=0

We add all the numbers together, and all the variables

-21x+6=0

We move all terms containing x to the left, all other terms to the right

-21x=-6

x=-6/-21

x=2/7

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