(2x+6)/5=(x-1)/2

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Solution for (2x+6)/5=(x-1)/2 equation: 



(2x+6)/5=(x-1)/2

We move all terms to the left:

(2x+6)/5-((x-1)/2)=0

We calculate fractions


2x/()+(-((x-1)*5)/()=0



We calculate terms in parentheses: +(-((x-1)*5)/(), so:

-((x-1)*5)/(

We multiply all the terms by the denominator


-((x-1)*5)



We calculate terms in parentheses: -((x-1)*5), so:

(x-1)*5

We multiply parentheses

5x-5

Back to the equation:

-(5x-5)



We get rid of parentheses

-5x+5

Back to the equation:

+(-5x+5)



We get rid of parentheses

2x/()-5x+5=0

We multiply all the terms by the denominator


2x-5x*()+5*()=0

We add all the numbers together, and all the variables

2x-5x*()=0

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