(2x+64)+(3x+22)+(3x+22)=180

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Solution for (2x+64)+(3x+22)+(3x+22)=180 equation: 



(2x+64)+(3x+22)+(3x+22)=180

We move all terms to the left:

(2x+64)+(3x+22)+(3x+22)-(180)=0

We get rid of parentheses

2x+3x+3x+64+22+22-180=0

We add all the numbers together, and all the variables

8x-72=0

We move all terms containing x to the left, all other terms to the right

8x=72

x=72/8

x=9

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