(2x+7)(2+x)=0

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Solution for (2x+7)(2+x)=0 equation:



(2x+7)(2+x)=0
We add all the numbers together, and all the variables
(2x+7)(x+2)=0
We multiply parentheses ..
(+2x^2+4x+7x+14)=0
We get rid of parentheses
2x^2+4x+7x+14=0
We add all the numbers together, and all the variables
2x^2+11x+14=0
a = 2; b = 11; c = +14;
Δ = b2-4ac
Δ = 112-4·2·14
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3}{2*2}=\frac{-14}{4} =-3+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3}{2*2}=\frac{-8}{4} =-2 $

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