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(2x+7)(4x-5)=0
We multiply parentheses ..
(+8x^2-10x+28x-35)=0
We get rid of parentheses
8x^2-10x+28x-35=0
We add all the numbers together, and all the variables
8x^2+18x-35=0
a = 8; b = 18; c = -35;
Δ = b2-4ac
Δ = 182-4·8·(-35)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-38}{2*8}=\frac{-56}{16} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+38}{2*8}=\frac{20}{16} =1+1/4 $
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