(2x+7)(x+3)=4

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Solution for (2x+7)(x+3)=4 equation:



(2x+7)(x+3)=4
We move all terms to the left:
(2x+7)(x+3)-(4)=0
We multiply parentheses ..
(+2x^2+6x+7x+21)-4=0
We get rid of parentheses
2x^2+6x+7x+21-4=0
We add all the numbers together, and all the variables
2x^2+13x+17=0
a = 2; b = 13; c = +17;
Δ = b2-4ac
Δ = 132-4·2·17
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{33}}{2*2}=\frac{-13-\sqrt{33}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{33}}{2*2}=\frac{-13+\sqrt{33}}{4} $

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