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(2x+7)(x+4)=108
We move all terms to the left:
(2x+7)(x+4)-(108)=0
We multiply parentheses ..
(+2x^2+8x+7x+28)-108=0
We get rid of parentheses
2x^2+8x+7x+28-108=0
We add all the numbers together, and all the variables
2x^2+15x-80=0
a = 2; b = 15; c = -80;
Δ = b2-4ac
Δ = 152-4·2·(-80)
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{865}}{2*2}=\frac{-15-\sqrt{865}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{865}}{2*2}=\frac{-15+\sqrt{865}}{4} $
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