(2x+7)+(2x)+(2x+6)=(2x)+(3x+4)+(2x)

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Solution for (2x+7)+(2x)+(2x+6)=(2x)+(3x+4)+(2x) equation: 



(2x+7)+(2x)+(2x+6)=(2x)+(3x+4)+(2x)

We move all terms to the left:

(2x+7)+(2x)+(2x+6)-((2x)+(3x+4)+(2x))=0

We add all the numbers together, and all the variables

2x+(2x+7)+(2x+6)-(2x+(3x+4)+2x)=0

We get rid of parentheses

2x+2x+2x-(2x+(3x+4)+2x)+7+6=0



We calculate terms in parentheses: -(2x+(3x+4)+2x), so:

2x+(3x+4)+2x

We add all the numbers together, and all the variables

4x+(3x+4)

We get rid of parentheses

4x+3x+4

We add all the numbers together, and all the variables

7x+4

Back to the equation:

-(7x+4)



We add all the numbers together, and all the variables

6x-(7x+4)+13=0

We get rid of parentheses

6x-7x-4+13=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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